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Subject: 如何声明函数，才可以使用这种形式的调用？
zzzl (早安的空气)
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#1
Post at 2009-9-21 23:44  Profile | Blog | P.M.  | QQ
如何声明函数，才可以使用这种形式的调用？

begin
    fun([["a", "b"], [1, 2]]);
end
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freespace8
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#2
Post at 2009-9-22 10:51  Profile | Blog | P.M. 
procedure fun(const Args1, Args2: array of const);
begin
end;

try it~
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freespace8
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#3
Post at 2009-9-22 10:53  Profile | Blog | P.M. 
没仔细看帖。。。。这个就不知道了
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bahamut8348
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#4
Post at 2009-9-23 15:43  Profile | Blog | P.M. 
type
  t... = array [...] of array [...] of TVarRec
function ...(...: t...)...




做人要厚道，看帖要回贴
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zzzl (早安的空气)
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#5
Post at 2009-9-26 09:44  Profile | Blog | P.M.  | QQ
不行
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kendling (小冬)
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#6
Post at 2009-9-28 14:58  Profile | Site | Blog | P.M.  | QQ | Yahoo!
4楼的应该可行。




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zzzl (早安的空气)
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#7
Post at 2009-9-28 21:46  Profile | Blog | P.M.  | QQ
试过了啊，不行的啊
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jAmEs_
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#8
Post at 2009-9-29 10:47  Profile | Blog | P.M. 
一定要這樣調嗎？
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kendling (小冬)
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#9
Post at 2009-9-29 17:15  Profile | Site | Blog | P.M.  | QQ | Yahoo!
function ...(array of array of const):...

这样呢/




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zzzl (早安的空气)
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#10
Post at 2009-9-29 21:31  Profile | Blog | P.M.  | QQ
不行。。

也不是必需要这样，只是觉得[]能在参数里，[[]]也能应可行才对，呵呵
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jAmEs_
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#11
Post at 2009-9-29 23:26  Profile | Blog | P.M. 
呵呵，我也觉得，不过事实好像是不支持
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jjwwang
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#12
Post at 2009-11-10 11:50  Profile | Blog | P.M. 
begin
    fun( [  ['a', 'b'], ['1',' 2']  ] );
end

上面这样有办法声明,

下在的这样, 类型都不一样,估计没戏.

begin
    fun([["a", "b"], [1, 2]]);
end但
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